A synthesis reaction occurs between 15.0g of gallium and 15.0g oxygen.

1- Write a balanced equation.

Ga + 02 --> Gao2 (I got this part)

2- Setup two factor labels to determine the mass of product possible considering each reactant.

Please help #2. I don't understand the question.

Thanks

Are you sure that doesn't form Ga2O3?

4Ga + 3O2 ==> 2Ga2O3
mass Ga2O3 = mols Ga x (2 mols Ga2O3/4mols Ga) x molar mass Ga2O3.

mass Ga2O3 = mols O2 x (2 mols Ga2O3/3 mols O2) x molar mass Ga2O3.

Certainly! In order to determine the mass of the product possible in a synthesis reaction, we need to use stoichiometry and the concept of limiting reactants. Here's how you can set up the two factor labels to calculate the mass of the product:

1. Determine the limiting reactant: To do this, we compare the amount of each reactant to their respective stoichiometric coefficients in the balanced equation. The reactant that produces the fewer moles of product is the limiting reactant.

In this case, we have 15.0g of gallium (Ga) and 15.0g of oxygen (O2). To convert grams of each reactant into moles, we need to know their molar masses. The molar mass of Ga is approximately 69.7 g/mol, and for O2 it is 32.0 g/mol.

So, for gallium (Ga):
15.0g Ga x (1 mol Ga / 69.7 g Ga) = X mol Ga

And for oxygen (O2):
15.0g O2 x (1 mol O2 / 32.0 g O2) = X mol O2

2. Compare the moles of each reactant: Use the stoichiometry of the balanced equation to determine the mole ratio between the limiting reactant and the product.

From the balanced equation, we know that 2 moles of gallium (Ga) react with 1 mole of oxygen (O2) to form 2 moles of gallium oxide (Ga2O).

For gallium:
X mol Ga x (2 mol Ga2O / 2 mol Ga) = X mol Ga2O

And for oxygen:
X mol O2 x (2 mol Ga2O / 1 mol O2) = X mol Ga2O

3. Calculate the mass of the product: Now, convert the moles of the limiting reactant into grams of the product using the molar mass of gallium oxide (Ga2O), which is approximately 197.7 g/mol.

For gallium:
X mol Ga2O x (197.7 g Ga2O / 1 mol Ga2O) = X g Ga2O

And for oxygen:
X mol Ga2O x (197.7 g Ga2O / 1 mol Ga2O) = X g Ga2O

By following these steps, you can determine the mass of the product possible considering each reactant. Just remember to perform the calculations for both reactants and compare the results to find the limiting reactant and its corresponding mass of the product.