#1.) A 3.0 kg computer printer is pushed across a desk at a rate of 0.6m/ s2 (towards the right). Determine the force applied to the printer
#2.) If a 0.9 kg apple falls from a tree and hits the ground with a force of 8.82 N calculate the acceleration of the apple.
#3.) Calculate the mass of the truck that has a weight equal to 19600 N on Earth.
#4.) A car's airbag will activate and increase the stopping time of a passenger time from 1.0 x 10 -2s to 3.0 x 10 -1s. If the person in the car has a mass of 70.0 kg and the car is travelling at 100km/h (approximately 28 m/s). Determine the magnitute of force that the person will exert on the airbag.
Please show how you got all your answers including the answers.
#1.) To determine the force applied to the printer, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the printer (m) = 3.0 kg
Acceleration (a) = 0.6 m/s^2
Using the formula F = ma, we can substitute the values:
F = 3.0 kg * 0.6 m/s^2
Calculating the multiplication:
F = 1.8 N
Therefore, the force applied to the printer is 1.8 Newtons.
#2.) To calculate the acceleration of the apple when it hits the ground, we can use Newton's second law of motion again.
Given:
Mass of the apple (m) = 0.9 kg
Force (F) = 8.82 N
Using the formula F = ma, we can rearrange the formula to solve for acceleration:
a = F / m
Substituting the values:
a = 8.82 N / 0.9 kg
Calculating the division:
a ≈ 9.8 m/s^2
Therefore, the acceleration of the apple when it hits the ground is approximately 9.8 m/s^2.
#3.) To calculate the mass of the truck, we can use Newton's second law of motion and the gravitational force formula.
Given:
Weight of the truck (W) = 19600 N (on Earth)
Acceleration due to gravity (g) = 9.8 m/s^2 (on Earth)
The weight of an object is equal to mass multiplied by acceleration due to gravity:
W = mg
Rearranging the formula to solve for mass:
m = W / g
Substituting the values:
m = 19600 N / 9.8 m/s^2
Calculating the division:
m ≈ 2000 kg
Therefore, the mass of the truck is approximately 2000 kg.
#4.) To determine the magnitude of force the person exerts on the airbag, we can use Newton's second law of motion and the equation for average force.
Given:
Mass of the person (m) = 70.0 kg
Initial stopping time (t1) = 1.0 x 10^-2 s
Final stopping time (t2) = 3.0 x 10^-1 s
Initial velocity of the car (v) = 100 km/h ≈ 28 m/s
The average force experienced by the person during deceleration can be calculated using the equation:
F = m * (change in velocity) / (change in time)
Change in velocity = (final velocity - initial velocity)
Change in time = (final stopping time - initial stopping time)
Substituting the values:
Change in velocity = 0 - 28 m/s = -28 m/s
Change in time = (3.0 x 10^-1 s) - (1.0 x 10^-2 s) = 0.29 s
Calculating the average force:
F = 70.0 kg * (-28 m/s) / (0.29 s)
Calculating the division:
F ≈ -680.4 N
Since force is a vector quantity, the magnitude of force is always positive. Therefore, the magnitude of force exerted on the airbag by the person is approximately 680.4 Newtons.