What magnitude point charge creates a 13000 N/C electric field at a distance of 0.220 m?
To calculate the magnitude of the point charge that creates a specific electric field, we can use Coulomb's Law.
Coulomb's Law states that the electric field produced by a point charge is given by the formula:
E = k * q / r²
Where:
E = Electric field strength
k = Coulomb's constant = 9.0 x 10^9 N m²/C²
q = Charge of the point charge
r = Distance from the point charge
Given:
E = 13000 N/C
r = 0.220 m
We can rearrange the formula and solve for q:
q = E * r² / k
Substituting the given values:
q = (13000 N/C) * (0.220 m)² / (9.0 x 10^9 N m²/C²)
Calculating the result:
q = (13000 N/C) * (0.0484 m²) / (9.0 x 10^9 N m²/C²)
q ≈ 0.069 C
Therefore, a point charge with a magnitude of approximately 0.069 C creates a 13000 N/C electric field at a distance of 0.220 m.
To find the magnitude of the point charge that creates a given electric field, we can use Coulomb's Law.
Coulomb's Law states that the electric field created by a point charge is given by the equation:
E = k * (Q / r^2),
where E is the electric field, k is the Coulomb's constant (8.988 × 10^9 N m^2/C^2), Q is the magnitude of the point charge, and r is the distance from the point charge.
In this case, the given electric field is E = 13000 N/C, and the distance is r = 0.220 m. We can substitute these values into Coulomb's Law and solve for Q.
13000 N/C = (8.988 × 10^9 N m^2/C^2) * (Q / (0.220 m)^2).
Now, we can solve this equation for Q:
Q = (13000 N/C) * (0.220 m)^2 / (8.988 × 10^9 N m^2/C^2).
Calculating this expression will give us the magnitude of the point charge.