If 3000ft/3 of air crossing an evaporator coil and is cooled from 75F to 55F, what would be the volume of air,in ft/3, exiting the evaporator coil?
Pressure remains the same while the absolute temperature drops from 535 to 515 R. The volume will decrease by a ratio 515/535 = 0.9626
The new volume will be 2888 ft^3.
Well, if we have 3000 ft/3 of air entering the evaporator coil and it's cooled from 75F to 55F, I'm sure that's one pretty chill air party! Now, to find the volume of air exiting the evaporator coil, we need to know how much air leaves the coil and how much stays inside for some more cooling fun. Unfortunately, that information is missing, so it looks like we don't have enough data to calculate the volume of air exiting the coil. Guess this air party's guest list will remain a mystery! 🎉
To find the volume of air exiting the evaporator coil, we need to know the specific conditions of the system. The information given does not provide enough details to determine the volume of air exiting the evaporator coil.
To find the volume of air exiting the evaporator coil, we need to know the change in temperature and the specific volume of air. The specific volume of air is the volume per unit mass of air.
To calculate the volume of air, we use the formula:
Volume = Mass / Specific Volume
Since we are given the change in temperature, we can use the ideal gas law to find the initial and final densities of air. The ideal gas law states that:
PV = nRT
Where:
P is the pressure of the gas
V is the volume
n is the number of moles of gas
R is the ideal gas constant
T is the temperature in Kelvin
Since we are dealing with a constant pressure process, we can simplify the equation to:
V1 / T1 = V2 / T2
Where:
V1 is the initial volume
T1 is the initial temperature
V2 is the final volume
T2 is the final temperature
Now, let's plug in the given values:
V1 / 75 = V2 / 55
We can cross multiply to solve for V2:
55V1 = 75V2
V2 = (55 / 75) * V1
Now we need to calculate the mass of air. We are given the amount of air in ft^3 (3000 ft^3/3), but we need the mass. We can use the relationship between volume, density, and mass:
Density = Mass / Volume
Rearranging the equation, we find:
Mass = Density * Volume
Assuming air behaves as an ideal gas, we can use the ideal gas law and the given temperature and pressure (assuming atmospheric pressure) to find the density of air:
Density = (Pressure * Molecular Weight) / (R * Temperature)
The molecular weight of air is approximately 29 g/mol and the ideal gas constant (R) is 0.0821 L * atm / K * mol.
Once we have the density, we can calculate the mass of air flowing through the evaporator coil:
Mass = Density * Volume
Finally, we can calculate the volume of air exiting the evaporator coil using the formula:
Volume = Mass / Specific Volume
Note: The specific volume of air is the reciprocal of density since Specific Volume = 1/Density.
By following these steps, you should be able to calculate the volume of air exiting the evaporator coil.