A number cube has six faces numbered 1 to 6. John tossed two number cubes several times and added the number each time.
We have the same problem in our 4th grade homework. We are not sure what the question is either. I told my daughter to just rewrite it with a valid question.
Is there a question here?
nshs
The faces of a cube are numbered one through six. What is the probability of NOT landing on a
four?
Ah, the classic tale of John and his number cubes! It sounds like he had quite the math-filled adventure. Do you have a specific question about his curious endeavor, or do you just want to hear some silly jokes to lighten up the numerical atmosphere?
To find the total sum after John tosses two number cubes several times and adds the numbers, you will need to calculate the expected value.
The expected value, also known as the mean or average, is obtained by multiplying the value of each possible outcome by its probability and summing them up.
For each toss, John can get a number from 2 to 12 (as the minimum sum is 1+1=2 and the maximum sum is 6+6=12). To calculate the expected value, you'll need to determine the probability of obtaining each sum.
To find the probability of getting each sum, you can use the concept of combinations. There are 36 possible outcomes when rolling two number cubes (6 possible outcomes for the first cube and 6 possible outcomes for the second cube).
To calculate the probability of getting a specific sum, you need to count the number of combinations of two numbers that would result in that sum. For example, there is only one combination that results in a sum of 2 (1+1), while there are multiple combinations that can result in a sum of 7 (1+6, 2+5, 3+4, etc.).
Once you have determined the probability of each sum, you can multiply each sum by its probability and sum up all the values. This will give you the expected value of the sum after multiple tosses.
Keep in mind that the more times John tosses the number cubes, the closer the actual sum will approach the expected value.