how do you solve for x

3.4e^(2-2n)-9=-4 I don't know what is the step by step process. Help please!

3.4e^(2-2n)-9=-4

3.4e^(2-2n) = 5
e^(2-2n) = 5/3.4 = 50/34 = 25/17

e^(2-2n) = 25/17
ln both sides

ln( e^(2-2n) ) = ln (25/17)
(2-2n) lne = ln25 - ln17 , but lne = 1
2-2n = ln25-ln17
notice I have yet to touch a calculator ....

-2n = ln25 - ln17 - 2
n= (-1/2)ln25 + (1/2)ln17 + 1 , now to the calculator....
= appr .8072

To solve for x in the equation 3.4e^(2-2n) - 9 = -4, we need to isolate the variable x. Here's a step-by-step process:

Step 1: Add 9 to both sides of the equation to move the constant term to the right side:
3.4e^(2-2n) = -4 + 9
3.4e^(2-2n) = 5

Step 2: Divide both sides of the equation by 3.4 to isolate e^(2-2n):
e^(2-2n) = 5/3.4
e^(2-2n) ≈ 1.470588

Step 3: Take the natural logarithm (ln) of both sides of the equation to cancel out the exponential function:
ln(e^(2-2n)) = ln(1.470588)
2-2n ≈ ln(1.470588)

Step 4: Solve for n by isolating the variable:
-2n ≈ ln(1.470588) - 2
-2n ≈ -0.127833
n ≈ (-0.127833)/(-2)
n ≈ 0.0639165

Therefore, the solution for x is approximately n = 0.0639165.

1mooiu 578resuaosnmuaesrasoppumllakkesa oolces aalos m lo anmloivnmollasacsrloaos a uslo 32.0cvtñlo ñp wqaslop e c aes asrarscbvytlotaseaesays

easiiuoooiascea
ervcdgtvmaks 3acsea sra asis rea esc <lalioisv ahhs
cawcacsrsfs dsvs rs sfvs
aa agbscvrv a4scacdslo poak rsgreaha s4ecs s