how much heat energy needed to convert 125g ice 27 deg C to 50 deg C
To calculate the heat energy needed to convert a substance from one temperature to another, you can use the specific heat capacity (c), which represents the amount of heat needed to raise the temperature of a specific substance by a certain amount.
First, let's break down the steps to calculate the total heat energy needed:
1. Calculate the heat energy required to raise the temperature of the ice from its initial temperature (-27 °C) to its melting point (0 °C).
2. Calculate the heat energy required to melt the ice at its melting point (0 °C).
3. Calculate the heat energy required to raise the temperature of the melted ice (water) from its melting point (0 °C) to the desired final temperature (50 °C).
4. Add up the three calculated values to get the total heat energy.
Now, let's go through each step:
1. To raise the temperature of the ice from -27 °C to 0 °C, we will use the specific heat capacity of ice. The specific heat capacity of ice is 2.09 J/g°C.
Heat energy = mass × specific heat capacity × temperature change
Heat energy = 125 g × 2.09 J/g°C × (0 °C - (-27 °C))
2. To melt ice at its melting point (0 °C), we need to add heat energy known as the heat of fusion. The heat of fusion for ice is 334 J/g.
Heat energy = mass × heat of fusion
Heat energy = 125 g × 334 J/g
3. To raise the temperature of the melted ice (water) from 0 °C to 50 °C, we will use the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C.
Heat energy = mass × specific heat capacity × temperature change
Heat energy = 125 g × 4.18 J/g°C × (50 °C - 0 °C)
4. Finally, add up the three calculated values to get the total heat energy:
Total heat energy = step 1 + step 2 + step 3
By substituting the values into the equations provided above, you can calculate the total heat energy needed to convert 125 g of ice at -27 °C to 50 °C.