sodium metal dissolves im liquid mercury to form of NA(s) and Hg(l) are 0.97 g/ml and 13.6 g/ml respectively. a sodium amalgoum is made by dissolving 10 ml Na (s) in 20.0 ml Hg (l). The final volume of solution is 21.0 ml. Calculate the molarity of Na in the solution.
Convert volume Na to grams using density, then convert to mol. mol = grams/molar mass.
M Na = mols Na/total volume in L.
To find the molarity (M) of sodium in the solution, we need to determine the number of moles of sodium and divide it by the volume of the solution in liters.
1. First, let's determine the number of moles of sodium (Na). We can use the formula:
Moles = Mass / Molar mass
The molar mass of sodium (Na) is 23.0 g/mol.
Moles of Na = Mass of Na / Molar mass of Na
= 10 ml Na (s) * 0.97 g/ml / 23.0 g/mol
2. Next, let's find the number of moles of mercury (Hg). The given volume of mercury is 20.0 ml.
Moles of Hg = Mass of Hg / Molar mass of Hg
= 20.0 ml Hg (l) * 13.6 g/ml / 200.6 g/mol
3. Now, let's calculate the total moles of sodium in the solution. Since sodium amalgam is formed, we assume that all sodium atoms become part of the solution.
Total moles of Na = Moles of Na
4. The final volume of the solution is given as 21.0 ml. We need to convert it to liters.
Volume of solution = 21.0 ml / 1000 ml/L
5. Finally, let's calculate the molarity (M) of sodium in the solution using the formula:
Molarity (M) = Moles of Na / Volume of solution
Now you can substitute the values into the equation and calculate the molarity of sodium in the solution.