confrused with this one too let f(x)=x^2+6 and g (x) =4x-5 find (f ° g)(-7)
still don't get it and no one responds to my replys after the tutors assist
Hey look, I have the calculus problems too
check below I got 1095
You had at least one reply.
http://www.jiskha.com/display.cgi?id=1205707088
To find (f ° g)(-7), you need to perform function composition between f(x) and g(x). Function composition involves applying one function to the output of another function.
Let's start by finding g(-7). We substitute -7 into g(x) and solve for the result:
g(x) = 4x - 5
g(-7) = 4(-7) - 5 [Substitute -7 for x]
g(-7) = -28 - 5
g(-7) = -33
Now that we have g(-7) = -33, we can substitute this value into f(x) and solve for (f ° g)(-7):
f(x) = x^2 + 6
f(g(-7)) = (-33)^2 + 6 [Substitute -33 for x]
f(g(-7)) = 1089 + 6
f(g(-7)) = 1095
Therefore, (f ° g)(-7) = 1095.