Use the shell method to find the volume of the solid formed by rotating the region bounded by y=x^3, y=0, x=0, and x=2 about the line x=3.

To find the volume of the solid formed by rotating the region bounded by the curves around the line x=3 using the shell method, follow these steps:

Step 1: Sketch the Region
Begin by sketching the region bounded by the curves. In this case, y=x^3, y=0, x=0, and x=2. The region lies between the x-axis and the curve y=x^3, from x=0 to x=2.

Step 2: Determine the Axis of Rotation
Identify the line about which the region is being rotated. In this case, the region is being rotated around the line x=3.

Step 3: Set Up the Shell Method Integral
The shell method involves integrating the circumference (2πr) multiplied by the height (the differential length along the x-axis). To set up the integral, we need to express the circumference and height in terms of x.

Step 4: Find the Height
The height of each shell is the difference between the x-coordinate at the curve y=x^3 and the x-coordinate at the line x=3, which is 3-x.

Step 5: Find the Circumference
Since the axis of rotation is the vertical line x=3, the radius (r) of each shell is the distance between the x-coordinate at the curve y=x^3 and the axis of rotation (x=3), which is 3-(x^3)/3.

Step 6: Set Up the Integral
To set up the integral, we need to integrate the volume of each shell from x=0 to x=2. The integral can be written as:

V = ∫[a,b] 2πrh dx

where a and b are the limits of integration (in this case, a=0 and b=2), h is the height (3-x), and r is the radius (3-(x^3)/3). Thus, the integral becomes:

V = ∫[0,2] 2π(3-(x^3)/3)(3-x) dx

Step 7: Solve the Integral
Evaluate the integral to find the volume of the solid. Integrate the expression with respect to x, plugging in the limits of integration:

V = 2π ∫[0,2] (3-(x^3)/3)(3-x) dx

Solving this integral will yield the volume of the solid formed by rotating the given region about the line x=3.

Please note that computing the definite integral for this specific problem can be quite complex and require advanced calculus techniques.