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A) How do you make 200 mL of a 0.1 M solution of a substance that has a molecular weight of 121.1 g/mol? Answer I got: 200mL = 1/0.1M x 1/(121.1g/mol) x mass of the substance. mass of the substance = 0.2L x 0.1M x 121.1g/mol=2.42g

Algebra
Find the square root of 121 A. 11* B. 11 C.12 D.13

Math
1) x^2 + 22x + k = (xr)^2 Given constants r and k, the above equation is true for all values of x. What is the value of the sum of r and k? I'm thinking it's 110, because to get 22x, r has to be 11, and that would mean k = 121.

math 115
1. find the square root 121= 11 11*11=121 is this correct? 2.carlos works 8.25h. and receives $102.30 pay. what will he receive at the rate if he worked 14h?= carlos rate of pay is $12.40 per h. $173.60 is this correct? 3. write

Biochemistry
How do you prepare 100 mL of a 0.1 M TRISHCl buffer with a pH 7.4 using solid TRIS base (MW 121.1) and 1 M hydrochloric acid? I started with pH=pKa + log ([Tris]/[Tris+] [Tris]/[Tris+]= 10^(7.48.06]=0.219 so 0.219:1 ratio with

math
estimate 58% of 121 by using 10%. show your work. thanks so much

math
A tower casts a shadow 11 feet long. The distance from the top of the tower to the end of the shadow is 61 feet. how many feet tall is the tower? 61Squared = 11squared = h squared 3721 = 121 + h squared 121 = 121 3600 = h

Geometry
The area of a square is 121 sq feet. What is the length of its sides? Would I find this by dividing 121 by 4?

As chemistry
A SAMPLE OF ANTIMONY, Ar=121.8, WAS ANALYSED AND WAS FOUND TO CONSIST OF 60% OF 121Sb AND ONE OTHER ISOTOPE. DETERMINE THE MASS NUMBER OF THE OTHER ISOTOPE IN THE SAMPLE OF ANTIMONY. please help I'm really stuck, Chemistry 

Calculus
integrate: (square root of (y^2 121))/y dy, y>11. I got (12(square root of (y^2121))/12 sec^1 (y/12) +C but it's not right. I'm not sure where I am going wrong.

Math
write an expression to describe the rule for the pattern. 1, 4, 13, 40, 121, ...

algebra
what is the value of c so that x^211x+c makes a perfect trinomial A. 121 B.121 over 4 C.11/2 D.121/2 i think it is B
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