a frame with a 19"permitter and 2"wide
what is the length of this frame and what is the area.
To find the length of the frame, we need to subtract twice the width from the perimeter.
Given:
Perimeter = 19 inches
Width = 2 inches
First, we find the total length of all four sides of the frame by multiplying the width by 2 and subtracting it from the perimeter:
Total length of all four sides = Perimeter - 2 * Width
= 19 inches - 2 inches * 2
= 19 inches - 4 inches
= 15 inches
Therefore, the length of the frame is 15 inches.
To find the area of the frame, we need to subtract the area of the inner rectangle from the area of the outer rectangle.
The area of the outer rectangle is calculated by multiplying the length and width:
Area of outer rectangle = Length * Width
= 15 inches * 2 inches
= 30 square inches
The area of the inner rectangle can be found by subtracting the area of the inner rectangle from the area of the outer rectangle:
Width of inner rectangle = Width of outer rectangle - 2 * Width
= 2 inches - 2 inches * 2
= 2 inches - 4 inches
= -2 inches (negative value is not possible, so it means the inner rectangle does not exist)
Therefore, the area of the frame is equal to the area of the outer rectangle, which is 30 square inches.