Assume the solubility of benzoic acid in ice-cold water is 1.70 g/L and the solubility of benzoic acid in hot water is 68.0 g/L. Calculate the minimum volume of water (in mL) needed to recrystallize 0.350 g of benzoic acid.
This should be solved the same way that you would solve for volume if density was given to you instead of solubility.
Solubility=g/L
So mass of benzoic acid/solubility in H20= volume needed in L
Perform this step for each of the solubilities and multiply your answer by 10^3 to convert from L to mL.
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To calculate the minimum volume of water needed to recrystallize benzoic acid, we need to determine the conditions under which the solubility is reached. In this case, we have the solubility of benzoic acid in both ice-cold water and hot water.
The solubility is given as 1.70 g/L in ice-cold water and 68.0 g/L in hot water. We can use this information to set up the following equation:
Mass of benzoic acid / solubility in water = Volume of water
Let's calculate the volume of ice-cold water needed:
Volume of ice-cold water = Mass of benzoic acid / solubility in ice-cold water
Given:
Mass of benzoic acid = 0.350 g
Solubility in ice-cold water = 1.70 g/L
Volume of ice-cold water = 0.350 g / 1.70 g/L
Converting grams to milliliters:
Volume of ice-cold water = (0.350 g / 1.70 g/L) x (1000 mL/ 1 L)
Volume of ice-cold water = (0.350 g / 1.70) x (1000 / 1) mL
Volume of ice-cold water = 205.9 mL
Therefore, a minimum volume of 205.9 mL of ice-cold water is needed to recrystallize 0.350 g of benzoic acid.