Two equal circles of radius 8cm intersect at X and Y. If the line joining the centers is 12cm long, find the length of XY.
with solution pls, tnx...
let the length of the overlap be x
then 8+8-x=12
x=4
So now you can construct a right-angled triangle by joining one of the centres to X
Its hypotenue will be 8
and its base will be 8 - (1/2)of4 = 6 and its height is 1/2 of XY, call it h
h^2 + 6^2 = 8^2
h^2 = 64-36 = 28
h = √28 = 2√7
So XY = 4√7