(2^(4+pi))/ 2^(1+pi)
remember, when dividing powers with the same base ...
we keep the base and subtract the exponents
4+π - (1+π)
= 4+π-1-π = 3
so
(2^(4+pi))/ 2^(1+pi)
= 2^3
= 8
we keep the base and subtract the exponents
4+π - (1+π)
= 4+π-1-π = 3
so
(2^(4+pi))/ 2^(1+pi)
= 2^3
= 8