Write an equation in point slope form of a line parallel to 12x-2y=6 and passes through the point (-4,-3)
To find an equation in point-slope form of a line parallel to the given line and passing through the point (-4, -3), we first need to determine the slope of the given line.
Let's rewrite the given equation in slope-intercept form (y = mx + b) by isolating y:
12x - 2y = 6
-2y = -12x + 6
y = 6x - 3
From this equation, we can see that the slope of the given line is 6.
Since the line we are looking for is parallel to the given line, it will also have a slope of 6.
Now that we have the slope (m) and a point (-4, -3), we can use the point-slope form of a line:
y - y1 = m(x - x1)
Plugging in the values, we get:
y - (-3) = 6(x - (-4))
Simplifying further:
y + 3 = 6(x + 4)
Thus, the equation in point-slope form of a line parallel to 12x - 2y = 6 and passing through the point (-4, -3) is:
y + 3 = 6(x + 4)