The density of a fresh water is 1000 kg/m^3 a 12 cm side cube is submerged to a depth of 30 cm 1-cauculate the pressure at:a-the bottom surface of the cube
B-the top surface of the cube
2-calculate the force entered by water on each surface
2.943 KPa
To calculate the pressure at the bottom and top surfaces of the cube, we can use the formula:
Pressure = Density × Acceleration due to gravity × Depth
1) Pressure at the bottom surface of the cube:
- Since the cube is submerged to a depth of 30 cm (or 0.3 m), we can calculate the pressure using the formula mentioned above:
Pressure = 1000 kg/m^3 × 9.8 m/s^2 × 0.3 m
Pressure = 2940 Pa (Pascals)
2) Pressure at the top surface of the cube:
- The pressure at the top surface will be the same as the pressure at the bottom surface because the cube is submerged in a stationary liquid, like fresh water in this case. The pressure only changes with depth and does not depend on the area or shape.
To calculate the force exerted by the water on each surface of the cube, we can use the formula:
Force = Pressure × Area
To find the area of each surface of the cube, we need to calculate the surface area:
Surface Area = (side length)^2 = (0.12 m)^2 = 0.0144 m^2
Now we can calculate the force exerted by the water on each surface:
1) Force on the bottom surface of the cube:
Force = Pressure × Area = 2940 Pa × 0.0144 m^2
Force = 42.336 N (Newtons)
2) Force on the top surface of the cube:
Since the pressure at the top is the same as the bottom, the force on the top surface will also be the same:
Force = Pressure × Area = 2940 Pa × 0.0144 m^2
Force = 42.336 N (Newtons)
Therefore, the force exerted by the water on each surface of the cube is 42.336 Newtons.