Find the zeroes of the function
y=3x^3-3x
So I factored that to y=3x(x^2-1)
but am not sure about the zeroes. I know that 0 and 1 are zeroes, but am not sure how to get a zeroe from x^2.
Thanks.
Factor it again to get 3x (x+1)(x-1)
The zeroes are where any factor is zero, namely -1, 0 and 1.
wats 2+2