Suppose the battery on your phone delivers a current of 0.740 mA (that's milliAmperes) over a time of 4.00 hours. What is the total charge that flows out of the battery during this time?
AND
How many electrons flow out of the battery during this time?
I=q/t =>
q=It=0.74•10⁻³•4•3600=10.66 C,
N=q/e=10.66/1.6•10⁻¹⁹=6.66•10¹⁹
what law of vectors
To find the total charge that flows out of the battery during this time, we can use the formula:
Q = I * t
Where:
Q is the total charge in Coulombs
I is the current in Amperes
t is the time in seconds
First, we need to convert the current from milliAmperes to Amperes. Since 1 Ampere is equal to 1000 milliAmperes, we can calculate the current as:
I = 0.740 mA / 1000 = 0.000740 A
Next, we need to convert the time from hours to seconds. Since 1 hour is equal to 3600 seconds, we can calculate the time as:
t = 4.00 hours * 3600 seconds/hour = 14400 seconds
Now, we can calculate the total charge:
Q = 0.000740 A * 14400 s = 10.656 Coulombs
Therefore, the total charge that flows out of the battery during this time is 10.656 Coulombs.
To find the number of electrons that flow out of the battery during this time, we need to know the charge of one electron. The charge of an electron is approximately -1.602 x 10^-19 Coulombs.
To find the number of electrons, we can use the formula:
Number of electrons = Total charge / Charge of one electron
Substituting the values:
Number of electrons = 10.656 Coulombs / -1.602 x 10^-19 Coulombs
Calculating this gives us:
Number of electrons = -6.66 x 10^19 electrons
Since the number of electrons cannot be negative, it indicates that 6.66 x 10^19 electrons flow out of the battery during this time.