calculate the specific heat for 18.5-g sample of tin that absorbs 183 J when its temp increases from 35.0 degrees celcius to 78.6 degress celcius. I don't know where to even start, help?
Note the correct spelling of celsius.
q = mass Sn x specific heat x (Tfinal-Tinitial)
183 = 18.5g x sp.h. x (78.6-35.0)
Solve for sph.
The distance between the centers of two atoms in a diatomic molecule is 1.22 angstroms. (An angstrom is 10-10 m.) Calculate the distance in feet.
To calculate the specific heat of the sample of tin, we can use the formula:
q = m * c * ΔT
Where:
q is the heat absorbed (in Joules)
m is the mass of the sample (in grams)
c is the specific heat of the substance (in J/g °C)
ΔT is the change in temperature (in °C)
In this case, we are given:
q = 183 J
m = 18.5 g
ΔT = (78.6 °C - 35.0 °C) = 43.6 °C
Rearranging the formula, we can solve for c:
c = q / (m * ΔT)
Now we can substitute the given values:
c = 183 J / (18.5 g * 43.6 °C)
Calculating this expression will give us the specific heat of tin.
To calculate the specific heat for the sample of tin, you can use the formula:
q = m * c * ΔT
where:
- q is the heat absorbed or released,
- m is the mass of the substance,
- c is the specific heat, and
- ΔT is the change in temperature.
Given values:
- q = 183 J (absorbed heat)
- m = 18.5 g (mass of tin)
- ΔT = (78.6°C - 35.0°C) = 43.6°C (change in temperature)
First, convert the mass of tin from grams to kilograms by dividing it by 1000:
m = 18.5 g ÷ 1000 = 0.0185 kg
Next, plug the values into the formula and solve for c:
183 J = 0.0185 kg * c * 43.6°C
Simplifying the equation further:
183 J = 0.805 kg°C * c
Now, isolate c by dividing both sides of the equation by 0.805 kg°C:
c = 183 J / (0.0185 kg * 43.6°C)
Finally, calculate c to find the specific heat:
c = 0.998 J/(g·°C)
Therefore, the specific heat of the tin sample is approximately 0.998 J/(g·°C).