A 0.35 m2 coil with 50 turns produces a maximum emf of 45 volts in a magnetic field of 0.4 Tesla. What is the speed of rotation of the coil?
To find the speed of rotation of the coil, we can use the equation:
emf = B * A * N * ω
Where:
emf is the electromotive force (in volts)
B is the magnetic field strength (in Tesla)
A is the area of the coil (in square meters)
N is the number of turns in the coil
ω is the angular velocity (in radians per second)
In this case, we know:
emf = 45 volts
B = 0.4 Tesla
A = 0.35 square meters
N = 50 turns
To find ω, we rearrange the equation:
ω = emf / (B * A * N)
Substituting the given values:
ω = 45 / (0.4 * 0.35 * 50)
Now we can calculate ω:
ω = 45 / (0.07 * 50)
ω = 45 / 3.5
ω = 12.857 radians per second
Therefore, the speed of rotation of the coil is approximately 12.857 radians per second.