A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is the value of the rms current in the coil if the coil has the resistance of 3.3 Ù?
Have no idea how to do this...
To find the value of the rms current in the coil, we need to use the formula for the current in a rotating coil in a magnetic field, which is given by:
I = BANω / R
Where:
I = rms current in the coil
B = magnetic field strength (in Tesla)
A = area of the coil (in square meters)
N = number of turns in the coil
ω = angular velocity of the coil (in radians per second)
R = resistance of the coil (in ohms)
We are given the following values:
B = 0.6 Tesla
A = 0.35 m^2
N = 50 turns
ω = 5 radians per second
R = 3.3 ohms
Now we can substitute these values into the formula and calculate the current:
I = (0.6 Tesla) * (0.35 m^2) * (50 turns) * (5 radians per second) / (3.3 ohms)
First, we multiply the terms in the numerator:
I = (0.6 * 0.35 * 50 * 5) Tesla * m^2 * turns * radians per second / (3.3 ohms)
Then, we divide by the resistance:
I = (0.6 * 0.35 * 50 * 5) Tesla * m^2 * turns * radians per second / 3.3 ohms
Now, we can simplify the expression:
I = 0.6 * 0.35 * 50 * 5 / 3.3 * Tesla * m^2 * turns * radians per second
Finally, we calculate the value of I:
I = 2.38095238095 Tesla * m^2 * turns * radians per second / 3.3 ohms
Therefore, the value of the rms current in the coil is approximately 0.722 Amperes.