My numerator is 10 less than my denaminator. I am equal to 3/5
3/5 = 6/10 = 9/15 = 12/20 = 15/25 = 18/30
(x-10)/x = 3/5
3 x = 5(x-10)
3 x = 5 x - 50
2 x = 50
x = 25
15/25
To solve this problem, let's call the numerator "x" and the denominator "y."
According to the given information, the numerator is 10 less than the denominator. This can be expressed as: x = y - 10.
We are also told that the fraction is equal to 3/5. We can represent this as: x/y = 3/5.
Now we have two equations: x = y - 10 and x/y = 3/5.
To find the values of x and y, we can use substitution. Substitute the value of x from the first equation into the second equation:
(y - 10) / y = 3 / 5.
To solve this equation, we can cross multiply:
5(y - 10) = 3y.
Expanding the left side:
5y - 50 = 3y.
Combining like terms:
5y - 3y = 50.
2y = 50.
Finally, divide both sides by 2:
y = 25.
Now that we have the value of y, we can substitute it back into the first equation to find the value of x:
x = 25 - 10.
x = 15.
Therefore, the numerator is 15 and the denominator is 25, and the fraction is equal to 15/25, which simplifies to 3/5.