The sum of four consecutive multiples of 5 is 230. What is the greatest of these numbers ?
n +(n+5) + (n+10) + (n+15) = 230 (we want n + 15)
4 n + 30 = 230
4 n = 200
n = 50
n+15 = 65
thank you
50,55,60 and 65
Are the fourth consecutive of 5 whose sum is 230
Thank you it helped so much
50;55 .60.65
To find the greatest of four consecutive multiples of 5, we need to set up an equation. Let's call the first number x.
The four consecutive multiples of 5 would be x, x + 5, x + 10, and x + 15.
According to the problem, the sum of these four numbers is 230. So we can write the equation as:
x + (x + 5) + (x + 10) + (x + 15) = 230
Now, let's solve this equation to find the value of x.
Combine the terms on the left-hand side of the equation:
4x + 30 = 230
Subtract 30 from both sides:
4x = 200
Divide both sides by 4:
x = 50
Now that we have found the value of x, let's find the greatest of these numbers by substituting x into the equation:
x + 15 = 50 + 15 = 65
Therefore, the greatest of these numbers is 65.
230 / 4 = 57.5
Does that give you a clue?