How many grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution?

39.0% w/v means 39.0 sucrose in 100 mL solution. You want 875 mL; therefore,

39.0g x 875mL/100mL = ? g sucrose for 875 mL soln.

To calculate the number of grams of sucrose needed to make a 39.0% (w/v) sucrose solution, follow these steps:

Step 1: Convert the percentage concentration to a decimal.
39.0% can be converted to 0.39.

Step 2: Calculate the grams of sucrose per milliliter.
0.39 grams of sucrose per milliliter of solution.

Step 3: Multiply the grams per milliliter by the total volume of the solution.
0.39 grams/ml * 875 ml = 341.25 grams.

Therefore, 341.25 grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution.

To find out how many grams of sucrose are needed to make a 39.0% (w/v) sucrose solution, we need to use the formula:

mass = volume × concentration

where:
- mass is the mass of sucrose (in grams)
- volume is the volume of the solution (in milliliters)
- concentration is the percentage of sucrose in the solution (in grams per 100 mL)

Given:
- volume = 875 mL
- concentration = 39.0% (w/v)

First, we need to convert the given volume from milliliters to liters. There are 1000 milliliters in a liter, so:

volume = 875 mL ÷ 1000 = 0.875 L

Next, we need to calculate the mass by rearranging the formula:

mass = volume × concentration

mass = 0.875 L × 39.0 g/100 mL

Now, we can cancel out the liters and milliliters:

mass = 0.875 × 39.0 g = 34.125 g

Therefore, approximately 34.125 grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution.

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