How many grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution?
39.0% w/v means 39.0 sucrose in 100 mL solution. You want 875 mL; therefore,
39.0g x 875mL/100mL = ? g sucrose for 875 mL soln.
To calculate the number of grams of sucrose needed to make a 39.0% (w/v) sucrose solution, follow these steps:
Step 1: Convert the percentage concentration to a decimal.
39.0% can be converted to 0.39.
Step 2: Calculate the grams of sucrose per milliliter.
0.39 grams of sucrose per milliliter of solution.
Step 3: Multiply the grams per milliliter by the total volume of the solution.
0.39 grams/ml * 875 ml = 341.25 grams.
Therefore, 341.25 grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution.
To find out how many grams of sucrose are needed to make a 39.0% (w/v) sucrose solution, we need to use the formula:
mass = volume × concentration
where:
- mass is the mass of sucrose (in grams)
- volume is the volume of the solution (in milliliters)
- concentration is the percentage of sucrose in the solution (in grams per 100 mL)
Given:
- volume = 875 mL
- concentration = 39.0% (w/v)
First, we need to convert the given volume from milliliters to liters. There are 1000 milliliters in a liter, so:
volume = 875 mL ÷ 1000 = 0.875 L
Next, we need to calculate the mass by rearranging the formula:
mass = volume × concentration
mass = 0.875 L × 39.0 g/100 mL
Now, we can cancel out the liters and milliliters:
mass = 0.875 × 39.0 g = 34.125 g
Therefore, approximately 34.125 grams of sucrose are needed to make 875 mL of a 39.0% (w/v) sucrose solution.