5ml of 8N HN03, 4.8ml of 5N HCL and a certain volume of 17M H2s04 are mixed together and made up to 2 liter 30ml of this acid mixture exactly neutralize 42.9ml of na2c03, 10 H2O in 100ml of water. Calculate the amount of sulphate 10m in gm present in solution
The 6.5gm who help
Your post makes no sense to me. (sulphate 10m in gm??). The 6.5gm who help?
To determine the amount of sulfate (SO4 2-) present in the solution, we need to follow these steps:
Step 1: Determine the number of moles of sodium carbonate (Na2CO3) used in the neutralization reaction.
We know that 42.9 ml of Na2CO3 solution was neutralized by the acid mixture.
Given that the concentration of Na2CO3 is 10 g/L and the volume used is 100 ml (0.1 L), we can calculate the number of moles of Na2CO3 using the formula:
Number of moles = concentration (in mol/L) x volume (in L)
= 10 g/L x 0.1 L
= 1 mol
Step 2: Determine the molar ratio between Na2CO3 and H2SO4.
From the balanced chemical equation of the neutralization reaction between Na2CO3 and H2SO4:
Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2
We can see that one mole of Na2CO3 reacts with one mole of H2SO4, meaning the molar ratio between them is 1:1.
Step 3: Calculate the number of moles of H2SO4 used in the neutralization.
Since the molar ratio between Na2CO3 and H2SO4 is 1:1, the number of moles of H2SO4 used in the neutralization is also 1 mol.
Step 4: Calculate the amount of H2SO4 in grams.
To calculate the mass of H2SO4 (in grams), we need to use its molar mass, which is:
Molar mass of H2SO4 = (2 x 1.008 g/mol for H) + (32.06 g/mol for S) + (4 x 16.00 g/mol for O)
= 98.09 g/mol
The amount of H2SO4 in grams can be calculated using the formula:
Amount in grams = number of moles x molar mass
Amount of H2SO4 = 1 mol x 98.09 g/mol
= 98.09 g
Therefore, the amount of sulfate (SO4 2-) present in the solution is 98.09 grams.
To calculate the amount of sulfate (SO4^2-) in grams present in the solution, we need to go step by step.
Step 1: Determine the moles of Na2CO3.10H2O reacted.
The given volume of Na2CO3 solution is 42.9 mL, and its concentration is not specified. To calculate the moles of Na2CO3, we need its molarity (M).
Step 2: Calculate the molarity of Na2CO3 solution.
The molarity (M) is calculated using the formula:
Molarity (M) = Moles of solute / Volume of solution (L)
Step 3: Calculate the moles of Na2CO3.
Moles of Na2CO3 = Molarity (M) x Volume (L)
Step 4: Determine the number of moles of sulfate (SO4^2-) formed.
In the reaction between Na2CO3 and H2SO4, one mole of Na2CO3 reacts with one mole of H2SO4 to produce one mole of SO4^2-. Therefore, the moles of SO4^2- formed will be equal to the moles of Na2CO3.
Step 5: Calculate the amount of sulfate (SO4^2-) in grams.
To calculate the amount of sulfate in grams, we need the molar mass of sulfate. The molar mass can be calculated by adding up the atomic masses of the elements present in the sulfate ion (SO4^2-).
Step 6: Calculate the mass of sulfate (SO4^2-) in grams.
Mass of SO4^2- = Moles of SO4^2- x Molar mass of SO4^2-
Please provide the molarity of the Na2CO3 solution so that we can proceed with the calculations.