For the oxidation of glucose ( C6H12O6 + 2O2---6H2O +6CO2), how many moles of O2 will it take to consume 6 moles of glucose. Can someone explain it?
In chemistry you can, with the help of a balanced chemical equation, convert anything to anything. The coefficients in the balanced equation are used for that purpose. First, the equation you wrote is not balanced. The proper equation is
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
?mols O2 = 6 mols glucose x (6 mols O2/1 mol glucose) = 6*(6/1) = 36 mols O2.
The answer is 36
To determine how many moles of O2 are needed to consume 6 moles of glucose, we can use the balanced equation for the oxidation of glucose: C6H12O6 + 6O2 → 6H2O + 6CO2.
From the balanced equation, we can see that 1 mole of glucose reacts with 6 moles of O2. So, to find out how many moles of O2 are needed to consume 6 moles of glucose, we simply multiply the number of moles of glucose (6) by the stoichiometric coefficient of O2 (6).
6 moles of glucose * 6 moles of O2/mole of glucose = 36 moles of O2.
Therefore, it will take 36 moles of O2 to consume 6 moles of glucose during the oxidation process.