I need help on a balance ionic equation in chemistry
Ca(NO3)2 + NaOH
Ca^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + 2OH^-(aq) ==> Ca(OH)2(s) + 2Na^+(aq) + 2NO3^-(aq)
Net ionic is
Ca^2+(aq) + 2OH^-(aq) ==> Ca(OH)2(s)
To balance the ionic equation for the reaction between Ca(NO3)2 and NaOH, you need to follow these steps:
Step 1: Write the unbalanced equation.
Start by writing the chemical equation for the reaction:
Ca(NO3)2 + NaOH --> Ca(OH)2 + NaNO3
Step 2: Separate the compounds into their individual ions.
Break down each compound into its respective ions:
Ca(NO3)2: Ca²⁺ + 2NO3⁻
NaOH: Na⁺ + OH⁻
Ca(OH)2: Ca²⁺ + 2OH⁻
NaNO3: Na⁺ + NO3⁻
Step 3: Determine the balanced equation by swapping and combining ions.
By swapping the ions between compounds, we can find the balanced equation:
Ca²⁺ + 2NO3⁻ + 2Na⁺ + 2OH⁻ --> Ca²⁺ + 2OH⁻ + 2Na⁺ + 2NO3⁻
Step 4: Simplify the equation.
Remove any ions that appear on both sides of the equation:
Ca²⁺ + 2NO3⁻ + 2Na⁺ + 2OH⁻ --> Ca²⁺ + 2OH⁻ + 2Na⁺ + 2NO3⁻
Step 5: Balance the equation.
To balance the equation, make sure the number of each type of ion is the same on both sides:
Ca²⁺ + 2NO3⁻ + 2Na⁺ + 2OH⁻ --> Ca²⁺ + 2OH⁻ + 2Na⁺ + 2NO3⁻
The equation is already balanced, with an equal number of calcium (Ca²⁺), hydroxide (OH⁻), sodium (Na⁺), and nitrate (NO3⁻) ions on both sides.