Air in the vicinity of a local power station contains 8.8x10^-4 gm^-3 SO2. What volume of 0.001moldm^-3 Iodine solution would be required to react with a solution obtained from 200dm^3 of contaminated air?
The equation given is
SO2 + I2 + 2H2O ==> H2SO4 + 2HI
Thanks! :)
I would help, but im a little bit confused about some of your notations
gm^-3
moldm^-3
dm^3
Someone else may come along and help, but just in case a clarification would be nice.
gm^-3 = g/m^3
moldm^-3 = mol/dm^3 = mols/L = M
dm^3 = L
1 mole of SO2= 1 mole of I2=2 moles of H2O.
Density=mass/volume, solve for vol.
Density*volume=mass=(8.8x10^-4 g/m^3)* 220 m^3= g of SO2.
g of SO2/molecular weight of SO2= moles of SO2
Since the reaction requires 1 mole of SO2 to react with 1 mole of I2, the moles that were calculated for SO2 must equal to moles of I2.
Molarity=moles/Liters
Solve for liters,
Liters of I2 required=moles/Molarity=moles of SO2/0.001 of I2
Dr.Bob222,
You could have just posted a solution.
To find the volume of the iodine solution required to react with the solution obtained from 200 dm^3 of contaminated air, we need to follow these steps:
Step 1: Calculate the number of moles of sulfur dioxide (SO2) in the air.
Given: The concentration of SO2 in the air is 8.8×10^-4 gm^-3.
We know the molar mass of SO2 is 64.06 g/mol.
To calculate the number of moles, we use the formula:
Number of moles = mass / molar mass.
Since we have the concentration in grams per cubic meter (gm^-3), we multiply the concentration by the volume of air to get the mass of SO2.
Mass of SO2 = concentration of SO2 × volume of air.
Mass of SO2 = 8.8×10^-4 gm^-3 × (200 dm^3) = 0.176 g.
To find the number of moles of SO2, we divide the mass by the molar mass:
Number of moles of SO2 = Mass of SO2 / Molar mass of SO2.
Number of moles of SO2 = 0.176 g / 64.06 g/mol ≈ 0.00275 mol.
Step 2: Calculate the number of moles of iodine (I2) required to react with the given number of moles of SO2.
From the balanced equation, we can see that 1 mole of SO2 reacts with 1 mole of I2.
So, the number of moles of I2 required will be the same as the number of moles of SO2:
Number of moles of I2 = Number of moles of SO2 ≈ 0.00275 mol.
Step 3: Calculate the volume of the iodine solution required.
Given: The concentration of the iodine (I2) solution is 0.001 moldm^-3.
We can use the formula: Volume (dm^3) = Number of moles / Concentration.
Volume of iodine solution = 0.00275 mol / 0.001 moldm^-3 ≈ 2.75 dm^3.
Therefore, approximately 2.75 dm^3 (or 2750 cm^3) of the 0.001 moldm^-3 iodine solution would be required to react with the solution obtained from 200 dm^3 of contaminated air.