A rectangle is 5 times as long as it is wide. If the area is 125 square feet, find its perimeter.

A = LW

125 = 25 * 5

P = 2L + 2W

P = 50 + 10

P = 60 feet

P= 2l + 2w

P=250 + 50 =300

To find the perimeter of the rectangle, we need to first find the length and width of the rectangle.

Let's assume the width of the rectangle is "w".

According to the given information, the length of the rectangle is 5 times the width. Therefore, the length can be represented as "5w".

The formula to calculate the area of a rectangle is A = length * width.

In this case, the area is given as 125 square feet. So we can write the equation as:

125 = 5w * w

Now, we can solve this equation to find the width, "w":

125 = 5w^2

Divide both sides by 5:
25 = w^2

Taking the square root of both sides:
w = √25

So, the width of the rectangle is 5 feet.

Now, we can find the length of the rectangle:
Length = 5w = 5 * 5 = 25 feet.

To find the perimeter of the rectangle:
Perimeter = 2 * (length + width)
= 2 * (25 + 5)
= 2 * 30
= 60 feet.

Therefore, the perimeter of the rectangle is 60 feet.