I have forgotten how to do ratios...Please help.

The standard ratio of(number of treatments) and (total mL dose) are 3.5 to 2mL. If only 2 treatments are given, how many total mL doses are given?

(2/3.5)* 2 ml = 1.14 ml

To solve this problem, we can set up a proportion using the given ratio and the number of treatments. Here's how:

Step 1: Set up the proportion using the given ratio:
(Number of treatments) / (Total mL dose) = 3.5 / 2

Step 2: Since we know that only 2 treatments are given, we can substitute this value into the proportion:
2 / (Total mL dose) = 3.5 / 2

Step 3: Cross multiply the values in the proportion:
2 * 2 = 3.5 * (Total mL dose)

Step 4: Simplify the equation:
4 = 3.5 * (Total mL dose)

Step 5: Solve for the unknown variable, Total mL dose:
(Total mL dose) = 4 / 3.5

Step 6: Calculate the value of Total mL dose:
(Total mL dose) ≈ 1.14

Therefore, if only 2 treatments are given, the total mL doses given would be approximately 1.14 mL.

To solve this problem, we need to understand the concept of ratios. In simple terms, a ratio is a way to compare two quantities. Ratios are typically written in the form of fractions, using a colon (:) or the word "to" to separate the two quantities being compared.

In this case, the ratio given is 3.5 to 2, which means that for every 3.5 treatments, there are 2 mL of dose. Now, let's solve the problem:

Since the ratio given is 3.5 to 2, we can write this as a fraction: 3.5/2. This means that for every 3.5 treatments, there are 2 mL of dose.

If only 2 treatments are given, we need to find out how many total mL doses are given. To do this, we can set up a proportion to find the missing value.

Let's set up the proportion:

3.5/2 = x/2

In this proportion, x represents the total mL doses given for 2 treatments.

Now, let's solve the proportion:

Cross-multiplying, we get:

3.5 * 2 = 2 * x

7 = 2x

To isolate x, divide both sides of the equation by 2:

7/2 = x

Therefore, for 2 treatments, a total of 3.5 mL doses are given.

And that's how you solve the problem!