Adam drew two same size rectangles and divided them into the same number of eqal parts. He shaded 1/3 of one rectangle and 1/4 of the other rectangle. What is the least number of parts into which both rectangles could be divided?
12
12 bc if you FRICKING USE GOOGLE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
12
um I don't know lol I asked the question :P it's 12 lol I copied the others
HMMMMM....... how about “I don’t know” I was thinking on here for answers BUT IDK what happened srry : P
swer much
To find the least number of parts into which both rectangles could be divided, we need to find the least common multiple (LCM) of the denominators 3 and 4.
To do that, we can list the multiples of 3 and 4 until we find a common multiple:
Multiples of 3: 3, 6, 9, 12, 15, 18, 21, ...
Multiples of 4: 4, 8, 12, 16, 20, 24, ...
As we can see, the least common multiple of 3 and 4 is 12, which means the rectangles must be divided into at least 12 equal parts for both fractions to be represented accurately.
Therefore, the least number of parts into which both rectangles could be divided is 12.