a simple hwk question.. i don't understand what i need to do..
1-butanol (shown below) burns in the presence of oxygen to give off carbon dioxide and water by the following reaction:
C4H9OH + 6 O2 ==> 4 CO2 + 5 H2O
If 40.88 mL of 1-butanol burns completely, how many grams of 1-butanol have burned? grams
(Hint: The density of 1-butanol is 0.810 g/mL)
30
To solve this homework question, you need to calculate the mass of 1-butanol that has burned. Here's how you can do it:
1. Start by using the given density of 1-butanol: 0.810 g/mL. This means that for every 1 mL of 1-butanol, it weighs 0.810 grams.
2. The question states that 40.88 mL of 1-butanol has burned completely. Multiply this volume by the density to find the mass:
Mass of 1-butanol = Volume of 1-butanol x Density of 1-butanol
= 40.88 mL x 0.810 g/mL
= 33.1348 grams
Therefore, 33.1348 grams of 1-butanol have burned.