Determine the moles of aluminum acetate,AL(C2H3O2)3,that can be made if you do this reaction with 12 moles of acetic acid (C2H3O2H)
C2H3O2H+AL(OH)3->AL(C2H3O2)3+3H2O
The reaction is not balanced. First balance the reaction before attempting to solve, which I have already done for you.
3C2H3O2H+AL(OH)3----->AL(C2H3O2)3+3H2O
12 mols of C2H3O2H *( 1 mol of AL(C2H3O2)3/3 mols of C2H3O2H)= 4 moles of AL(C2H3O2)3
To determine the moles of aluminum acetate (AL(C2H3O2)3) that can be made, we need to use the stoichiometry of the balanced equation.
The balanced equation tells us that 1 mole of acetic acid (C2H3O2H) reacts with 1 mole of aluminum hydroxide (AL(OH)3) to produce 1 mole of aluminum acetate (AL(C2H3O2)3) and 3 moles of water (H2O).
Given that you have 12 moles of acetic acid (C2H3O2H), we can determine the number of moles of aluminum acetate that can be produced using the stoichiometric ratio of the reactants.
Since the stoichiometric ratio between acetic acid and aluminum acetate is 1:1, the number of moles of aluminum acetate produced will also be 12 moles.
Therefore, you can make 12 moles of aluminum acetate (AL(C2H3O2)3) by reacting it with 12 moles of acetic acid (C2H3O2H).