How much work is needed to stop a 20g bullet moving with a speed of 150ms-1
m-20g-0.02kg
v-150ms/1
k.e-1/2mv2
k.e-1/2*0.02*150*150
1/2 to decimal-
0.5*0.02*150*150
225joules
I don't know i am the one asking the question
How much work is needed to stop a 20kg bullet with a speed of 150 minutesHow much work is needed to stop a 20kg bullet with a speed of 150 minutes.
K. E =1/2MV²
MASS= 20g =20/1000
=0.02kg
V = 150ms-¹
K. E = 0.02*150*150/2
=225j