chemistry

if the relative atomic mass of natural copper is 63.54,calculate the proportions of the isotope 65cu and 63cu

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  1. 63x + 65(1-x) = 63.54
    x = .73

    so, 73% 63Cu and 27% 65Cu

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  2. How did you arrive at x=.73
    Please break the formula

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  3. The answer to that question is this: 63.54 - 63 =0.54
    65 - 63.54 = 1.46
    0.54+1.46=2
    0.54÷2 ×100= 27%
    1.46÷2 ×100= 73%
    And that's final.

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