I need to solve latent heat. It gives me the number of ice cubes and the mass in grams (7550 grams). It wants to know how many calories would burn turning the ice into body temperature water (if body temp is 37 degrees celsius.) It gives Lm of H2O=1,44 kcal.mol and cwater=1.0 cal/g*degrees celsius. I can't figure out how to set up this problem.
q = (mass ice x heat fusion) + [mass ice x specific heat H2O x Tfinal-Tinitial)]
heat fusion is 80 cal/gposted by DrBob222
So is the first part of the equation because it is in ice form and the second part because it is the change of temperature after it becomes water? And thank you for the answer.
One more question please. Do I need to convert to joules or can it be kept in cal/g? Thanks in advance