What mass of AlCl3 can be formed from 5.000 mol NiCl2 and 2.000 mol Al?

Al(s) + NiCl2(aq) → AlCl3(aq) + Ni(s)
I balanced it to
2Al + 2NiCl2 -> 2AlCl3 + 3Ni

I'm not sure how to go about this. I converted the moles into grams, but I feel like the balanced equation falls into play too. Am lost and a way to start would be good.

This is a limiting reagent problem. You know that because it lists amounts for BOTH reactants.

First the equation isn't balanced; you have 2 Ni on the left and 3 on the right.
2Al + 3NiCl2 ==> 2AlCl3 + 3Ni

Do these one at a time and use the coefficients in the balanced equation.
5.000 mols NiCl2 x (2 mols AlCl3/3 mol NiCl2) = 5*2/3 = 3.33 mols AlCl3

2.000 mols Al x (2 mols AlCl3/2 mol Al) = 2*2/2 =2 mol AlCl3.

Obviously both answers can't be right; the correct answer in limiting reagent problems is ALWAYS the smaller value.
Therefore, 2.000 mol AlCl3 wll be formed.

To find the mass of AlCl3 that can be formed, we need to use stoichiometry.

Step 1: Determine the molar ratios from the balanced equation.
From the balanced equation, we see that 2 moles of Al yield 2 moles of AlCl3. Therefore, the molar ratio of Al to AlCl3 is 2:2 or 1:1.

Step 2: Calculate the molar mass of AlCl3.
The molar mass of AlCl3 can be calculated by adding up the atomic masses of aluminum (Al) and chlorine (Cl):
Molar mass(AlCl3) = atomic mass(Al) + (3 × atomic mass(Cl))

Step 3: Convert moles of Al into grams of AlCl3.
Since we have the number of moles of Al, we can convert this to grams of AlCl3 using the molar mass of AlCl3.

Now, let's calculate the mass of AlCl3 using the given information:

Step 1: Since the molar ratio of Al to AlCl3 is 1:1, we can directly relate the moles of Al to the moles of AlCl3.

Step 2: The molar mass of AlCl3 is:
Molar mass(AlCl3) = (atomic mass(Al) + (3 × atomic mass(Cl)))
Molar mass(AlCl3) = (26.98 g/mol + (3 × 35.45 g/mol))

Step 3: Multiply the number of moles of Al by the molar mass of AlCl3 to get the mass of AlCl3:
Mass(AlCl3) = moles(Al) × molar mass(AlCl3)

Substituting the given values:
Mass(AlCl3) = 2.000 mol × (26.98 g/mol + (3 × 35.45 g/mol))

Now calculate the expression to find the mass of AlCl3.