how many grams of cai2 are present in 3.28 moles?
Can someone explaine how to do this question as well?
I would caution you that lower case letters don't tell me much.
grams = mols x molar mass.
CHEMISRTY IS SO FUN
To find the number of grams of CaI2 present in 3.28 moles, you need to use the molar mass of CaI2 and the given number of moles.
The molar mass of CaI2 can be found by adding up the atomic masses of calcium (Ca) and iodine (I) in the compound.
The atomic mass of calcium (Ca) is approximately 40.08 g/mol.
The atomic mass of iodine (I) is approximately 126.90 g/mol.
So the molar mass of CaI2 is:
(1 * 40.08 g/mol) + (2 * 126.90 g/mol) = 40.08 g/mol + 253.80 g/mol = 293.88 g/mol
Now you can calculate the number of grams of CaI2 present in 3.28 moles using the following formula:
Number of grams = Number of moles * Molar mass
Number of grams = 3.28 moles * 293.88 g/mol
Number of grams = 962.2464 g
Therefore, there are approximately 962.25 grams of CaI2 present in 3.28 moles.