Calculus - Partial Fractions

What is the integral of

7e^(7t)

Divided By

e^14t+13e^7t+36

Using partial fractions

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  1. Substitute t = Log(x)/7

    Integral is then proportional to:

    Integral of dx/[x^2 + 13 x + 36] =

    Integral of dx/[(x+4)(x+9)]

    1/[(x+4)(x+9)] = A/(x+4) + B/(x+9)

    Multiply both sides by x+4 and take limit x to -4:

    1/5 = A

    Multiply both sides by x+9 and take limit x to -9:

    1/5 = A

    -1/5 = B

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  2. Thank you so much.

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  3. I've reached the last step of

    (7/5) ln((x+4)/(x+9)

    But how do I substitute the variable 't' back in?

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  4. t = Log(x)/7 ---->

    x = exp(7 t)

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