1.8 mol Zn and 7.3 mol HCl react according

to the equation
Zn + 2 HCl −→ ZnCl2 + H2 .
If the limiting reactant is Zn, calculate the
amount of ZnCl2 formed.
Answer in units of mol

To determine the amount of ZnCl2 formed, we need to identify the limiting reactant in the given reaction. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed.

Let's calculate the moles of ZnCl2 that can be formed using the stoichiometry of the balanced equation:

Zn + 2 HCl → ZnCl2 + H2

From the equation, we can see that 1 mole of Zn reacts with 1 mole of ZnCl2. Therefore, the amount of ZnCl2 formed will be equal to the number of moles of Zn.

Given that we have 1.8 moles of Zn, the amount of ZnCl2 formed will also be 1.8 moles.

Thus, the amount of ZnCl2 formed is 1.8 mol.

answer is 8