An aircraft flying at a steady velocity of 70m/s eastwards at height of 800m drops a package of supplies
a)express the initial velocity of the package as vector.
B)how long will it take for the package to reach the ground?
C)how fast will it be going as it lands?(answer in vector form)
Show me the formula
a)70m/s b)12.8s c)√20900
show me the formula
What formula did you use?
I am not clear
A) To express the initial velocity of the package as a vector, we need both the magnitude and direction. Since the aircraft is flying eastwards, the initial velocity of the package will also be in the eastward direction. The magnitude of the initial velocity is given as 70 m/s. Therefore, the initial velocity of the package can be expressed as a vector as (70 m/s) eastward.
B) To find out how long it will take for the package to reach the ground, we need to determine the time it will take for the package to fall vertically from its initial height of 800m. We can use the equation of motion for vertical free fall:
h = (1/2) * g * t^2
where:
h = height (800m in this case)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
Rearranging the equation to solve for time (t), we have:
t = sqrt(2h/g)
Substituting the given values, we can calculate the time it takes for the package to reach the ground:
t = sqrt(2 * 800m / 9.8m/s^2)
t ≈ 12.81 seconds
Therefore, it will take approximately 12.81 seconds for the package to reach the ground.
C) The package will continue to move eastward at the same speed as the aircraft until it hits the ground. Since the aircraft is flying at a steady velocity of 70 m/s eastwards, the package will also have the same velocity when it lands. Hence, the velocity of the package as it lands can be expressed as a vector as (70 m/s) eastward.
A,70m/s
B,12.8s