A toy car moves down an incline with an acceleration of 20 cm/s/s. what will its velocity be in 5 sec? what distance will it have traveled..?
v = at = 20cm/s^2 * 5s = 100m/s
s = 1/2 at^2 = 1/2 * 20cm/s^2 * (5s)^2 = 250cm
To find the velocity and distance traveled by the toy car, we can use the equations of motion. The first equation relates velocity (v), acceleration (a), and time (t):
v = u + at
Where:
v = final velocity
u = initial velocity (assumed to be 0, as the car starts from rest)
a = acceleration
t = time
Given:
Acceleration (a) = 20 cm/s²
Time (t) = 5 seconds
1. Finding the velocity (v):
Substituting the given values into the equation of motion:
v = u + at
v = 0 + (20 cm/s²) * (5 s)
v = 100 cm/s
So, the velocity of the toy car after 5 seconds will be 100 cm/s.
2. Finding the distance traveled (s):
There is another equation that relates displacement (s), initial velocity (u), acceleration (a), and time (t):
s = ut + (1/2) * a * t²
For the toy car, as the initial velocity is 0, the above equation simplifies to:
s = (1/2) * a * t²
s = (1/2) * (20 cm/s²) * (5 s)²
s = (1/2) * (20 cm/s²) * (25 s²)
s = 1,250 cm
So, the toy car will have traveled a distance of 1,250 cm in 5 seconds.