What mass of glucose can be produced from
a photosynthesis reaction
that occurs using 21.2 mol CO2?
Answer in units of g
To find the mass of glucose produced, we need to use the balanced chemical equation for photosynthesis:
6 CO2 + 6 H20 → C6H12O6 + 6 O2
This equation tells us that for every 6 moles of CO2, we produce 1 mole of glucose (C6H12O6).
We know that the number of moles of CO2 is 21.2. We can use this information to find the number of moles of glucose produced:
Moles of glucose = (moles of CO2) / (coefficient of CO2 in the balanced equation)
The coefficient of CO2 in the balanced equation is 6.
Moles of glucose = 21.2 mol CO2 / 6
Moles of glucose = 3.53 mol
Finally, to find the mass of glucose produced, we need to multiply the number of moles of glucose by its molar mass. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.
Mass of glucose = (moles of glucose) x (molar mass of glucose)
Mass of glucose = 3.53 mol x 180.16 g/mol
Mass of glucose ≈ 635.75 g
Therefore, approximately 635.75 grams of glucose can be produced from the given 21.2 moles of CO2.
Write and balance the equation.
Using the coefficients in the balnced equation, convert 21.2 mol CO2 to mols glucose.
Then convert mols glucose to grams. g = mols x molar mass glucose.