H
/
benzene ring-N
\
CH3
select the class of compound from the choice below.
1-acetal
2-alcohol
3-alkene
4-amide
5-amine
6-carboxylic acid
7-ester
8-haloalkane
See above.
To determine the class of compound based on the given structure, we can analyze the functional groups present. Let's go through each choice and see if any of them match the structure:
1. Acetal: An acetal contains a central carbon atom bound to two oxygen atoms. The given structure does not have this functional group, so it is not an acetal.
2. Alcohol: An alcohol contains a hydroxyl group (-OH) bonded to a carbon atom. The given structure does not have this functional group, so it is not an alcohol.
3. Alkene: An alkene contains at least one carbon-carbon double bond. The given structure does not have a double bond, so it is not an alkene.
4. Amide: An amide contains a carbonyl group (C=O) bonded to a nitrogen atom (-N). The given structure does not have this functional group, so it is not an amide.
5. Amine: An amine contains a nitrogen atom bonded to at least one carbon atom. The given structure does have a nitrogen atom bonded to a carbon atom, so it could be an amine.
6. Carboxylic acid: A carboxylic acid contains a carbonyl group (C=O) and a hydroxyl group (-OH) bonded to a carbon atom. The given structure does not have this functional group, so it is not a carboxylic acid.
7. Ester: An ester contains a carbonyl group (C=O) bonded to an oxygen atom, which is further bonded to a carbon atom. The given structure does not have this functional group, so it is not an ester.
8. Haloalkane: A haloalkane contains at least one carbon-halogen (Cl, Br, I, etc.) bond. The given structure does not have a halogen atom, so it is not a haloalkane.
Based on this analysis, the closest match seems to be option 5: amine, considering the nitrogen atom bonded to a carbon atom.