if the H+ in acid mine drainage is 6.3 x 10^-5 mol/L, the pH of the drainage water is ___.

It would require ___ gal of 0.1 M
Ca(OH)2 (2 is a subscrip) to neutralize the proton acidity in 1000 gal of such drainage water.

pH = -log(H^+) = -log 6.3E-5 = ?

Ca(OH)2 + 2H^+ ==> 2H2O + Ca^2+
Convert 1000 gallons to L.
Then L x 6.3E-5 mol/L = mol H^+.
Mols Ca(OH)2 = 1/2 that (from the coefficients in the equation).
M Ca(OH)2 = mols Ca(OH)2/L Ca(OH)2. Yo know M and mols; solve for L and convert that to gallons Ca(OH)2.

9809237

To determine the pH of the drainage water, we can use the formula: pH = -log[H+]. Given that the concentration of H+ in the acid mine drainage is 6.3 x 10^-5 mol/L, we can substitute this value into the equation to find the pH.

pH = -log(6.3 x 10^-5)
pH ≈ -(-4.2)
pH ≈ 4.2

Therefore, the pH of the drainage water is approximately 4.2.

To determine the amount of Ca(OH)2 needed to neutralize the proton acidity in 1000 gal of the drainage water, we can use the stoichiometry of the reaction:

2 H+ + Ca(OH)2 -> Ca2+ + 2 H2O

From the balanced equation, we can see that for every 2 moles of H+, we need 1 mole of Ca(OH)2. Given that the concentration of H+ is 6.3 x 10^-5 mol/L and the volume of the drainage water is 1000 gal, we can calculate the moles of H+ present.

Moles of H+ = concentration × volume in L
Moles of H+ = 6.3 x 10^-5 mol/L × 1000 L
Moles of H+ = 6.3 x 10^-2 mol

Since we need 2 moles of H+ to neutralize 1 mole of Ca(OH)2, we divide the moles of H+ by 2 to get the moles of Ca(OH)2 required.

Moles of Ca(OH)2 = Moles of H+ / 2
Moles of Ca(OH)2 = 6.3 x 10^-2 mol / 2
Moles of Ca(OH)2 = 3.15 x 10^-2 mol

Finally, to find the volume of 0.1 M Ca(OH)2 solution required, we use the formula:

Volume of Ca(OH)2 solution = Moles of Ca(OH)2 / Concentration of Ca(OH)2

Volume of Ca(OH)2 solution = 3.15 x 10^-2 mol / 0.1 mol/L
Volume of Ca(OH)2 solution = 0.315 L or 315 mL

Therefore, it would require 315 mL (or 0.315 L) of 0.1 M Ca(OH)2 solution to neutralize the proton acidity in 1000 gal of such drainage water.