Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3
What is the volume in liters of 3.42 kg of this liquid?
mass = volume x density
Substitute and solve for volume (in cc) and convert to L.
To find the volume of a substance, we can use the formula:
Volume = Mass / Density
Given:
Density of ethylene glycol = 1.11 g/cm^3
Mass of ethylene glycol = 3.42 kg
First, let's convert the mass from kg to grams:
3.42 kg = 3.42 * 1000 g = 3420 g
Now we can substitute the values into the formula and solve for volume:
Volume = 3420 g / 1.11 g/cm^3
To convert the volume to liters, we need to convert the cm^3 to liters.
1 cm^3 = 1 mL
1 L = 1000 mL
So, divide the volume by 1000 to convert cm^3 to liters:
Volume (in liters) = (3420 g / 1.11 g/cm^3) / 1000
Calculating this, we get:
Volume (in liters) ≈ 3.08 L
Therefore, the volume of 3.42 kg of ethylene glycol is approximately 3.08 liters.