A total charge of 16ìC passes through a cross-sectional area of a nichrome wire in 4 s. How many electrons pass through the cross-sectional area in 16 s?
This has to do with Electric current and so i know that means 16ìC = 16 x 10^-6 = 1.6x10^-5.
q= 16 μC = 16•10⁻ ⁶ C,
t₁ = 4 s.
I=q/t₁=16•10⁻ ⁶/4=4•10⁻ ⁶ A,
N=I •t₂/e =4•10⁻ ⁶• 16/1.6•10⁻¹⁹ =4•10¹⁴ .
Thank you very much
To determine the number of electrons that pass through the cross-sectional area in 16 s, we need to use the charge of an electron. The charge of an electron is approximately -1.6 x 10^-19 C.
First, let's calculate the number of electrons that pass through the cross-sectional area in 4 s using the given charge of 16ìC:
Number of electrons = Total charge / Charge of one electron
Number of electrons = (16 x 10^-6 C) / (-1.6 x 10^-19 C)
Number of electrons = (16 x 10^-6) / (-1.6 x 10^-19)
Number of electrons = 10^13
So, in 4 s, approximately 10^13 electrons pass through the cross-sectional area.
Now, let's determine the number of electrons that pass through the cross-sectional area in 16 s:
Since we know that the number of electrons passing through the cross-sectional area is directly proportional to time, we can use a proportion to find the answer:
(Number of electrons in 16 s) / (Number of electrons in 4 s) = (Time in 16 s) / (Time in 4 s)
Let's substitute in the values we found earlier:
(Number of electrons in 16 s) / (10^13) = (16 s) / (4 s)
(Number of electrons in 16 s) = (10^13) x (16 s) / (4 s)
(Number of electrons in 16 s) = (10^13) x 4
(Number of electrons in 16 s) = 4 x 10^13
So, in 16 s, approximately 4 x 10^13 electrons pass through the cross-sectional area.
Therefore, the number of electrons that pass through the cross-sectional area in 16 s is 4 x 10^13.