if jay eats 1/3 of jelly beans and jack 1/4 of the jelly bean leveing bill with 10 jelly bean how many were there to start with
Let x = original jelly beans.
x - 1/3x - 1/4x = 10
This is assuming that Jack did NOT eat 1/4 of what remained after Jay ate 1/3.
60
To determine the initial number of jelly beans, we need to solve the problem step by step.
Let's assume the initial number of jelly beans is "x."
According to the problem, Jay eats 1/3 of the jelly beans, so (1/3)x jelly beans are eaten by Jay.
After Jay eats his portion, the remaining jelly beans will be (x - (1/3)x) = (2/3)x.
Next, Jack eats 1/4 of the remaining jelly beans, which is (1/4) * (2/3)x = (1/6)x jelly beans.
After Jack eats his portion, the remaining jelly beans will be (2/3)x - (1/6)x = (4/6)x - (1/6)x = (3/6)x = (1/2)x.
According to the problem, Bill is left with 10 jelly beans at the end. So, we can equate (1/2)x = 10.
To find the value of "x," we'll solve the equation:
(1/2)x = 10
To get rid of the fraction, we can multiply both sides by 2:
x = 10 * 2
x = 20
Therefore, the initial number of jelly beans was 20.