You are pushing a box up an inclined ramp. The force you exert on the box is 19·N up the ramp. The weight of the box is 100·N straight downward. The force friction exerts on the box is 8·N down the ramp. The normal force exerted on the box by the ramp is 50·N upward and at an angle, perpendicular to the ramp.

What is the magnitude of the force exerted by the box on you?

To find the magnitude of the force exerted by the box on you, we can use Newton's third law of motion, which states that every action has an equal and opposite reaction.

In this case, the force you exert on the box is the action force, and the force exerted by the box on you is the reaction force.

Since the force you exert on the box is given as 19 N up the ramp, the force exerted by the box on you will be equal in magnitude but in the opposite direction. Therefore, the force exerted by the box on you is 19 N down the ramp.

Note: Newton's third law tells us that the magnitude of the reaction force is equal to the magnitude of the action force, but the direction of the reaction force is always opposite to the direction of the action force.